Import Question JSON

Current Question (ID: 18871)

Question:
$\text{Lanthanide's most common oxidation state is:}$ $1.\ 2$ $2.\ 5$ $3.\ 3$ $4.\ 4$
Options:
  • 1. $2$
  • 2. $5$
  • 3. $3$
  • 4. $4$
Solution:
$\text{HINT: } +3 \text{ is the common oxidation state of lanthanides.}$ $\text{Step 1:}$ $\text{In lanthanides (At no. of elements 58 to 71) the electronic configuration of the three outermost shells are } (n-2)f^{1-14}(n-1)d^0ns^2.$ $\text{Lanthanides show variable oxidation state like } +2,+3,+4 \text{ and so on. But the most common oxidation state among these is } +3.$ $\text{Step 2:}$ $\text{Hence, the common oxidation state of lanthanides is } +3.$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}