Import Question JSON

Current Question (ID: 18873)

Question:
$\text{Actinoids show a greater number of oxidation states than lanthanoids because:}$
Options:
  • 1. $\text{4f- orbitals are more diffused than 5f-orbitals}$
  • 2. $\text{Lesser energy difference between 5f, and 6d orbitals than between 4f, and 5d orbitals}$
  • 3. $\text{More energy difference between 5f, and 6d orbitals than between 4f, and 5d orbitals}$
  • 4. $\text{More reactive nature of the actinoids than the lanthanoids.}$
Solution:
$\text{Actinoids show different oxidation states such as } +2, +3, +4, +5, +6 \text{ and } +7.$ $\text{However, } +3 \text{ oxidation state is most common among all the actinoids.}$ $\text{The wide range of oxidation states of actinoids is attributed to the fact that the 5f, 6d, and 7s energy levels are of comparable energies.}$ $\text{As the distance between the nucleus and 5f orbitals (actinides) is more than the distance between the nucleus and 4f orbitals (lanthanides) hence the hold of nucleus on valence electron decreases in actinides.}$ $\text{For this reason the actinoides exhibit more number of oxidation states in general.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}