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Current Question (ID: 18876)

Question:
$\text{The electronic configurations of Eu (Atomic no. 63), Gd (Atomic no. 64), and Tb (Atomic no. 65) are, respectively:}$
Options:
  • 1. $[\text{Xe}] 4f^6 5d^1 6s^2, [\text{Xe}]4f^7 5d^1 6s^2, \text{and } [\text{Xe}] 4f^9 6s^2$
  • 2. $[\text{Xe}] 4f^6 5d^1 6s^2, [\text{Xe}]4f^7 5d^1 6s^2, \text{and } [\text{Xe}]4f^8 5d^1 6s^2$
  • 3. $[\text{Xe}] 4f^7 6s^2, [\text{Xe}]4f^7 5d^1 6s^2, \text{and } [\text{Xe}] 4f^9 6s^2$
  • 4. $[\text{Xe}] 4f^7 6s^2, (\text{Xe})4f^8 6s^2, \text{and } [\text{Xe}]4f^8 5d^1 6s^2$
Solution:
$\text{Hint: All three elements belong to f block.}$ $\text{Explanation:}$ $\text{The electronic configuration of given elements is as follows:}$ $\text{Eu(63) = } [\text{Xe}] 4f^7 5d^0 6s^2$ $\text{Gd(64) = } [\text{Xe}] 4f^7 5d^1 6s^2$ $\text{Tb(65) = } [\text{Xe}] 4f^9 5d^0 6s^2$ $\text{Option 3 is correct}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}