Import Question JSON

Current Question (ID: 18878)

Question:

$\text{From the following, which is the most basic hydroxide?}$

Options:

1. $\text{Ce(OH)}_3$
2. $\text{Lu(OH)}_3$
3. $\text{Yb(OH)}_3$
4. $\text{Tb(OH)}_3$

Solution:

$\text{HINT: The basic character of hydroxide increases with an increase in metallic character.}$ $\text{STEP 1:}$ $\text{Basic nature of metal hydroxide} \propto \text{Metallic character}$ $\text{In the lanthanide series, as we move from left to right, the atomic radii and the ionic radii of tri positive lanthanide ions decrease from lanthanum to lutetium.}$ $\text{This change in size is observed due to increasing nuclear charge and electrons entering the inner 4f orbital which has poor shielding effect. This decrease in size with increasing atomic number is known as lanthanide contraction.}$ $\text{STEP 2:}$ $\text{As the size of lanthanides decreases across the series due to lanthanide contraction, we can say that the metallic character decreases, and the covalent character of the hydroxides increases.}$ $\text{Metal character decreases from Ce to Lu = Lanthanide contraction}$ $\text{So, Ce(OH)}_3 \text{ - Most basic and Lu(OH)}_3 \text{ - Least basic}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}