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Current Question (ID: 18883)

Question:

$\text{Consider the following statements:}$ $\text{a. Lanthanoid and actinoid belong to the f block and their general electronic}$ $\text{configuration is } nf^{1-14} n-1d^{0-1}ns^2.$ $\text{b. All lanthanides and actinoids show an oxidation state of +3.}$ $\text{c. The magnetic properties of the actinoids are more complex than those of}$ $\text{the lanthanoids.}$ $\text{d. Lanthanoids are comparatively less electropositive than actinides}$ $\text{Correct statements amongst the above are:}$

Options:

1. $\text{a, b}$
2. $\text{c, d, a}$
3. $\text{d, a, b}$
4. $\text{b, c, d}$

Solution:

$\text{Lanthanoid and actinoid belong to the f block and its general electronic}$ $\text{configuration is } (n-2)f^{1-14} n-1d^{0-1} ns^2.$ $\text{All lanthanides and actinoids show an oxidation state of +3. It is attained by}$ $\text{removing outermost 2 electrons of s electrons and 1 electron from f}$ $\text{electrons.}$ $\text{Magnetic properties of actinide complexes are borne by 5f open shell}$ $\text{orbitals. These orbitals have a marked inner shell character, as in}$ $\text{lanthanides, but interact more with the chemical environment than the 4f of}$ $\text{lanthanides, leading to unique magnetic properties.}$ $\text{Lanthanoids are comparatively less electropositive than actinides and due to}$ $\text{that reason, they are less reactive than actinides. Hence, the correct option}$ $\text{is the fourth option.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}