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Current Question (ID: 18901)

Question:

$\text{Highest oxidation state of manganese in fluoride is } +4 \text{ (MnF}_4\text{) but the highest oxidation state in oxides is } +7 \text{ (Mn}_2\text{O}_7\text{). The reason is:}$

Options:

1. $\text{Fluorine is more electronegative than oxygen.}$
2. $\text{Fluorine does not possess d orbitals.}$
3. $\text{Fluorine stabilizes lower oxidation state of Mn.}$
4. $\text{In covalent compounds, fluorine can only form a single bond while oxygen forms a double bond.}$

Solution:

$\text{Fluorine can only form single bond.}$ $\text{The highest oxidation state of manganese in fluoride is } +4 \text{ (MnF}_4\text{) but the highest oxidation state in oxides is } +7 \text{ (Mn}_2\text{O}_7\text{).}$ $\text{The reason is that in covalent compounds fluorine can form a single bond while oxygen forms a double bond.}$ $\text{1. Oxidation state of Mn in fluoride that is (MnF}_4\text{)}$ $\text{Let's consider Mn as } x,$ $x + 4(-1) = 0$ $x - 4 = 0$ $x = +4$ $\text{Hence, oxidation state is Mn is } +4$ $\text{2. Oxidation state of Mn in the oxide that is (Mn}_2\text{O}_7\text{) is-}$ $2x + 7(-2) = 0$ $2x + (-14) = 0$ $2x - 14 = 0$ $x = \frac{14}{2}$ $x = 7$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}