Import Question JSON

Current Question (ID: 19045)

Question:

$\text{Given below are two statements:}$ $\text{Statement I: We can get displacement from the acceleration-time graph.}$ $\text{Statement II: We can get acceleration from the velocity-time graph.}$

Options:

1. $\text{Both Statement I and Statement II are correct.}$
2. $\text{Both Statement I and Statement II are incorrect.}$
3. $\text{Statement I is correct and Statement II is incorrect.}$
4. $\text{Statement I is incorrect and Statement II is correct.}$

Solution:

$\text{Hint: } a = \frac{dv}{dt}$ $\text{Explanation: The acceleration-time graph shows how acceleration varies with time. To find displacement directly from an acceleration-time graph is not possible without additional steps.}$ $\text{We need to integrate the acceleration to get the velocity, and then integrate the velocity to get the displacement.}$ $\text{Therefore, Statement I is incorrect because displacement cannot be directly obtained from the acceleration-time graph.}$ $\text{The acceleration is the rate of change of velocity with respect to time. On a velocity-time graph, acceleration can be obtained by finding the slope (or gradient) of the graph.}$ $\text{Therefore, Statement II is correct because acceleration can be directly determined from the velocity-time graph.}$ $\text{Hence, option (4) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}