Import Question JSON

Current Question (ID: 19145)

Question:

$\text{A person standing on a spring balance inside a stationary lift measures 60 kg. The weight of that person if the lift descends with the uniform downward acceleration of 1.8 m/s}^2 \text{ will be: } [g = 10 \text{ m/s}^2]$

Options:

1. $321 \text{ N}$
2. $214 \text{ N}$
3. $163 \text{ N}$
4. $492 \text{ N}$

Solution:

$\text{Hint: The direction of pseudo force is opposite to the direction of acceleration of the system.}$ $\text{When lift is at rest}$ $N = mg$ $\Rightarrow 60 \times 10 = 600 \text{ N}$ $\text{When lift moves with downward acceleration, in frame of lift pseudo force will be in upward direction}$ $N' = M(g - a)$ $\Rightarrow 60(10 - 1.8)$ $N' \Rightarrow 492 \text{ N}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}