Import Question JSON

Current Question (ID: 19166)

Question:

$\text{A block remains in equilibrium as shown. If the mass, } m = \sqrt{3} \text{ kg,}$ $\text{what is the tension in the string?}$

Options:

1. $\sqrt{3}g \text{ N}$
2. $3g \text{ N}$
3. $\frac{g}{2} \text{ N}$
4. $\frac{g}{\sqrt{3}} \text{ N}$

Solution:

$\text{Hint: In the equilibrium condition, the net force is zero.}$ $\text{Step: Find the tension in the string in equilibrium.}$ $\text{The block is in equilibrium, then the net force acting on it must be zero i.e.,}$ $T = mg$ $\Rightarrow T = \sqrt{3}g \text{ N}$ $\text{Hence, option (1) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}