Import Question JSON

Current Question (ID: 19169)

Question:

$\text{A force of } 30 \text{ N is applied on a block of mass } 5 \text{ kg. the block travels a distance of } 50 \text{ m in } 10 \text{ s starting from rest. The coefficient of friction is:}$

Options:

1. $0.5$
2. $0.7$
3. $0.3$
4. $0.8$

Solution:

$\text{Applying Newtons' second law,}$ $30 - \mu mg = ma$ $\Rightarrow a = \left( \frac{30 - 50 \mu}{5} \right)$ $\text{As acceleration is uniform and block start from rest,}$ $S = \frac{1}{2} a t^2$ $\Rightarrow 50 = \frac{1}{2} \left( \frac{30 - 50 \mu}{5} \right) 10^2$ $\Rightarrow 50 = 30 - 50 \mu \Rightarrow \mu = \frac{25}{50} = 0.5$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}