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Current Question (ID: 19182)

Question:
$\text{A block of mass } 10 \text{ kg is kept on a rough inclined plane as shown in the figure. A force of } 3 \text{ N is applied to the block. The coefficient of static friction between the plane and the block is } 0.6. \text{ What should be the minimum value of force } P, \text{ such that the block does not move downward?}$ $\text{(take } g = 10 \text{ ms}^{-2})$
Options:
  • 1. $32 \text{ N}$
  • 2. $18 \text{ N}$
  • 3. $23 \text{ N}$
  • 4. $25 \text{ N}$
Solution:
$\text{Hint: } F = \mu N$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}