Import Question JSON

Current Question (ID: 19276)

Question:

$\text{Given below are two statements:}$ $\text{Statement I:}$ $\text{A truck and a car moving with equal kinetic energy are stopped by an equal retarding force. Both will cover equal distances to stop.}$ $\text{Statement II:}$ $\text{A car moving towards the east suddenly changes its direction towards the north with the same speed. In this case, its acceleration will be zero.}$

Options:

1. $\text{Both Statement I and Statement II are True.}$
2. $\text{Both Statement I and Statement II are False.}$
3. $\text{Statement I is True and Statement II is False.}$
4. $\text{Statement I is False and Statement II is True.}$

Solution:

$\text{Hint: } s = \frac{v^2}{2a}$ $\text{Explanation: Both the truck and the car had the same kinetic energy and hence same amount of work needed to be done.}$ $\text{As retarding force applied is the same for both, therefore, both the truck and the car travel the same distance before coming to rest.}$ $\text{Therefore, the stopping distance is independent of the mass of the vehicle and they will cover equal distance to stop.}$ $\text{As the direction of the car is changing, the acceleration of the car is non-zero.}$ $\text{Therefore, Statement I is True and Statement II is False.}$ $\text{Hence, option (3) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}