Import Question JSON

Current Question (ID: 19307)

Question:

$\text{The body of a man } 100 \text{ kg travelled } 10 \text{ m before coming to rest. If } \mu = 0.4, \text{ then work done against friction is: (motion is happening on a horizontal surface, take } g = 10 \text{ m/s}^2)$

Options:

1. $4500 \text{ J}$
2. $5000 \text{ J}$
3. $4200 \text{ J}$
4. $4000 \text{ J}$

Solution:

$W = F \cdot S$ $v^2 = 2 \times \mu g \cdot s$ $v^2 = 2 \times (0.4) \times 10 \times 10$ $v^2 = 80$ $\frac{v^2}{2a} = s \quad (a = \mu g)$ $w_f = \Delta k$ $= -\frac{1}{2} \times 100 \times 80$ $w_f = -4000$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}