Import Question JSON

Current Question (ID: 19359)

Question:

$\text{A metre scale is balanced on a knife edge at its centre. When two coins, each of mass 10 g are put, one on the top of the other at the } 10.0 \text{ cm mark, the scale is found to be balanced at the } 40.0 \text{ cm mark. The mass of the metre scale is found to be } x \times 10^{-2} \text{ kg. The value of } x \text{ is:}$

Options:

1. $3$
2. $4$
3. $5$
4. $6$

Solution:

$\text{Balance the torque:}$ $\left(0.02 \text{ g}\right) \times \left(30 \times 10^{-2} \right) = mg \times \left(10 \times 10^{-2} \right)$ $m = 0.06 \text{ kg} = 6 \times 10^{-2} \text{ kg}$ $\text{Therefore, } x = 6$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}