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$\text{Hint: Stress on his legs} = \frac{\text{weight}}{\text{area}} = \frac{V \rho g}{A}$ $\text{Step: Find the factor by which the stress changes.}$ $\text{Stress}(S) \text{ is defined by:}$ $S = \frac{\text{Force}}{\text{Area}}$ $\Rightarrow S = \frac{mg}{A} = \frac{(\text{Volume} \times \text{Density}) \times g}{\text{Area}}$ $\Rightarrow S = \frac{L^3 \times \rho \times g}{L^2} = L \rho g$ $\text{As seen in the equation above, stress depends on length, density, and acceleration due to gravity.}$ $\text{Since the density remains the same and gravity is constant, stress becomes directly proportional to the length.}$ $\Rightarrow S \propto L$ $\text{Then, we can write:}$ $\frac{S_1}{S_2} = \frac{L_1}{L_2} = \frac{9L_1}{L_1} = 9$ $\Rightarrow S_1 = 9S_2$ $\text{Therefore, the stress in the leg will change by the factor of 9.}$ $\text{Hence, option (1) is the correct answer.}$