Import Question JSON

Current Question (ID: 19554)

Question:

$\text{The bulk modulus of a liquid is } 3 \times 10^{10} \text{ Nm}^{-2}. \text{ The pressure required to reduce the volume of liquid by } 2\% \text{ is:}$

Options:

1. $3 \times 10^8 \text{ Nm}^{-2}$
2. $9 \times 10^8 \text{ Nm}^{-2}$
3. $6 \times 10^8 \text{ Nm}^{-2}$
4. $12 \times 10^8 \text{ Nm}^{-2}$

Solution:

$\text{Hint: } B = -\frac{P}{\Delta V / V}$ $\text{Step: Find the pressure required.}$ $B = -\frac{P}{\Delta V / V}$ $P = B \left( \frac{\Delta V}{V} \right)$ $= 3 \times 10^{10} \times \frac{2}{100}$ $= 6 \times 10^8 \text{ Nm}^{-2}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}