Import Question JSON

Current Question (ID: 19650)

Question:

$\text{A calorimeter of water equivalent } 20 \text{ g contains } 180 \text{ g of water at } 25^\circ \text{ C.}$ $'m' \text{ grams of steam at } 100^\circ \text{ C is mixed in it till the temperature of the mixture is } 31^\circ \text{ C.}$ $\text{The value of } 'm' \text{(in grams) is close to: (Latent heat of water } = 540 \text{ cal g}^{-1}, \text{ specific heat of water } = 1 \text{ cal g}^{-1}{}^\circ \text{C}^{-1})$

Options:

1. 2
2. 2.6
3. 4
4. 3.2

Solution:

$\text{Heat gained by the system (calorimeter and water) = heat lost by the steam.}$ $\frac{20 \times 1 \times (31 - 25) + 180 \times 1 \times (31 - 25)}{m \times 540 + m \times 1 \times (100 - 31)}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}