Import Question JSON

Current Question (ID: 19680)

Question:

$\text{Match List-I with List-II and choose the correct option:}$ $\begin{array}{|c|c|} \hline \text{List-I} & \text{List-II} \\ \hline (a) \ \text{Isothermal process} & (i) \ \text{Pressure constant} \\ (b) \ \text{Isochoric process} & (ii) \ \text{Temperature constant} \\ (c) \ \text{Adiabatic process} & (iii) \ \text{Volume constant} \\ (d) \ \text{Isobaric process} & (iv) \ \text{Heat content is constant} \\ \hline \end{array}$

Options:

1. $(a) \rightarrow (i), \ (b) \rightarrow (iii), \ (c) \rightarrow (ii), \ (d) \rightarrow (iv)$
2. $(a) \rightarrow (ii), \ (b) \rightarrow (iii), \ (c) \rightarrow (iv), \ (d) \rightarrow (i)$
3. $(a) \rightarrow (ii), \ (b) \rightarrow (iv), \ (c) \rightarrow (iii), \ (d) \rightarrow (i)$
4. $(a) \rightarrow (iii), \ (b) \rightarrow (ii), \ (c) \rightarrow (i), \ (d) \rightarrow (iv)$

Solution:

$\text{Hint: } \Delta Q = 0 \ \text{for the adiabatic process.}$ $\text{Step: Find the correct match.}$ $(a) \ \text{Isothermal} \Rightarrow \text{Temperature constant}$ $(a) \rightarrow (ii)$ $(b) \ \text{Isochoric} \Rightarrow \text{Volume constant}$ $(b) \rightarrow (iii)$ $(c) \ \text{Adiabatic} \Rightarrow \Delta Q = 0 \Rightarrow \text{Heat content is constant}$ $(c) \rightarrow (iv)$ $(d) \ \text{Isobaric} \Rightarrow \text{Pressure constant}$ $(d) \rightarrow (i)$ $\text{Therefore, the correct match is}$ $(a) \rightarrow (ii), \ (b) \rightarrow (iii), \ (c) \rightarrow (iv), \ (d) \rightarrow (i)$ $\text{Hence, option (2) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}