Import Question JSON

Current Question (ID: 19698)

Question:
$\text{A thermodynamic system is taken from an original state } D \text{ to an}$ $\text{intermediate state } E \text{ by a linear process, as shown in the figure. Its}$ $\text{volume is then reduced to the original volume from } E \text{ to } F \text{ by an}$ $\text{isobaric process. The total work done by the gas from } D \text{ to } E \text{ to } F$ $\text{will be:}$
Options:
  • 1. $-450 \text{ J}$
  • 2. $450 \text{ J}$
  • 3. $900 \text{ J}$
  • 4. $1350 \text{ J}$
Solution:
$\text{Hint: Work done by the gas = Area under } (P-V) \text{ curve.}$ $\text{Step: Find the work done by the gas.}$ $\text{The work done by the gas is equal to the area under the } P-V;$ $W = \frac{1}{2} \times 3 \times 300 = 450 \text{ J}$ $\text{Hence, option (2) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}