Import Question JSON

Current Question (ID: 19874)

Question:
$\text{Following statements are given:}$ $\text{(i) The average kinetic energy of a gas molecule decreases when the temperature is reduced.}$ $\text{(ii) The average kinetic energy of a gas molecule increases with increase in pressure at constant temperature.}$ $\text{(iii) The average kinetic energy of a gas molecule decreases with increases in volume.}$ $\text{(iv) Pressure of a gas increases with increase in temperature at constant pressure.}$ $\text{(v) The volume of gas decreases with increase in temperature.}$ $\text{Choose the correct answer from the options given below:}$
Options:
  • 1. $\text{(i) and (iv) only}$
  • 2. $\text{(i), (ii) and (iv) only}$
  • 3. $\text{(ii) and (iv) only}$
  • 4. $\text{(i), (ii) and (v) only}$
Solution:
$\text{The average kinetic energy of a gas molecule is directly proportional to the temperature.}$ $\text{Therefore, statement (i) is correct.}$ $\text{Statement (ii) is incorrect because kinetic energy depends on temperature, not pressure.}$ $\text{Statement (iii) is incorrect for the same reason.}$ $\text{Statement (iv) is correct as pressure increases with temperature at constant volume.}$ $\text{Statement (v) is incorrect as volume increases with temperature at constant pressure.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}