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$\text{Hint: } v \propto \sqrt{T}$ $\text{Step 1: Find the value of the temperature } T \text{ in } ^{\circ}\text{C.}$ $\text{The speed of sound at the temperature } T \text{ is } v_1 = 336 \text{ m/s.}$ $\text{By comparing given pressure wave } (P = 0.01 \sin[1000t - 3x] \text{ Nm}^{-2}) \text{ with the general equation } (P = P_0 \sin(\omega t - kx)) \text{ we get;}$ $\omega = 1000 \text{ rad/s}, k = 3 \text{ rad m}^{-1}$ $\text{Speed of sound at } 0^{\circ} \text{ is given by;}$ $v_2 = \frac{\omega}{k} = \frac{1000}{3}$ $\text{The velocity of sound is directly proportional to the square root of temperature i.e., } v \propto \sqrt{T}$ $\frac{v_1}{v_2} = \sqrt{\frac{T_1}{T_2}}$ $\Rightarrow \frac{336 \times 3}{1000} = \sqrt{\frac{T}{273}}$ $\Rightarrow \sqrt{\frac{T}{273}} = 1.008$ $\text{Squaring both sides we get;}$ $\frac{T}{273} = 1.008 \times 1.008 = 1.016064$ $\Rightarrow T = 1.016 \times 273 = 277.385 \text{ K} \approx 277 \text{ K}$ $\text{The temperature in degrees Celsius is given by;}$ $T(^{\circ}\text{C}) = T(\text{K}) - 273 \text{ K} = 277 - 273 = 4^{\circ}\text{C}$ $\text{Hence, option (1) is the correct answer.}$