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Current Question (ID: 20147)

Question:
$\text{Which of the following graphs depicts the variation of electric potential, } V \text{ with radial distance, } r \text{ from the centre of a positively charged conducting sphere of radius } R?$
Options:
  • 1. $\text{Graph 1}$
  • 2. $\text{Graph 2}$
  • 3. $\text{Graph 3}$
  • 4. $\text{Graph 4}$
Solution:
$\text{Hint: For conducting sphere potential is constant inside the sphere.}$ $\text{Explanation: As the electric field inside the charged conducting sphere is zero, the potential will be constant for the inside part.}$ $\text{The electric potential decreases for the outside part as the conducting sphere behaves like a point charge concentrated at the centre.}$ $\text{Therefore, the variation of the electric potential, } V \text{ with radial distance } r \text{ is shown in the figure below;}$$V = \frac{KQ}{R} \text{ for } r \leq R$$V = \frac{KQ}{r} \text{ for } r > R$$\text{Hence, option (3) is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}