Import Question JSON

Current Question (ID: 20225)

Question:

$\text{Four resistances } 40 \, \Omega, 60 \, \Omega, 90 \, \Omega \text{ and } 110 \, \Omega \text{ make the arms of a quadrilateral } ABCD. \text{ Across } AC \text{ is a battery of emf } 40 \, V \text{ and internal resistance negligible. The potential difference across } BD \text{ in } V \text{ is:}$

Options:

1. $4$
2. $3$
3. $2$
4. $1$

Solution:

$\text{Hint: } V = IR$ $i_1 = \frac{40}{40 + 60} = 0.4$ $i_2 = \frac{40}{90 + 110} = \frac{1}{5}$ $v_B + i_1(40) - i_2(90) = v_D$ $v_B - v_D = \frac{1}{5}(90) - \frac{4}{10} \times 40$ $v_B - v_D = 18 - 16 = 2$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}