Import Question JSON

Current Question (ID: 20226)

Question:

$\text{In the circuit, given in the figure currents in different branches and}$ $\text{value of one resistor are shown. Then potential at point } B \text{ with}$ $\text{respect to the point } A \text{ is:}$

Options:

1. $+1 \text{ V}$
2. $-1 \text{ V}$
3. $-2 \text{ V}$
4. $+2 \text{ V}$

Solution:

$\text{Hint: Apply Kirchhoff's loop rule.}$ $\text{Let us assume the potential at } A = V_A = 0$ $\text{Now at junction } C, \text{ According to KCL}$ $i_1 + i_3 = i_2$ $1 \text{ A} + i_3 = 2 \text{ A}$ $i_3 = 2 \text{ A}$ $\text{Now Analyse potential along } ACDB$ $V_A + 1 + i_3 (2) - 2 = V_B$ $0 + 1 + 2 (1) - 2 = V_B$ $V_B = 3 - 2$ $V_B = 1 \text{ Amp}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}