Import Question JSON

Current Question (ID: 20242)

Question:

$\text{As shown in the figure, in a steady state, the charge stored in the capacitor is } x \times 10^{-6} \text{ C. The value of } x \text{ is:}$

Options:

1. $20$
2. $10$
3. $30$
4. $40$

Solution:

$\text{Hint: In a steady state capacitor behaves as an open circuit.}$ $\text{Step 1: Find the charge stored in the capacitor.}$ $V_C = iR$ $\Rightarrow \frac{q}{C} = \frac{\varepsilon R}{r + R}$ $\frac{1.1 \times 10^{-6} \times 10 \times 100}{110} = 10 \times 10^{-6} \text{ C}$ $\text{Step 2: Find the value of } x.$ $\text{As } q = 10 \times 10^{-6}$ $\Rightarrow x = 10$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}