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Current Question (ID: 20257)

Question:
$\text{In the given circuit, the reading on the ideal voltmeter is equal to:}$
Options:
  • 1. $3 \text{ V}$
  • 2. $1.8 \text{ V}$
  • 3. $1.2 \text{ V}$
  • 4. $\text{zero}$
Solution:
$\text{Hint: } V = IR$ $\text{Step: Find the reading on the ideal voltmeter.}$ $\text{In the circuit diagram, the ideal voltmeter is given, which means resistance through the voltmeter is infinite, and current will not pass through it.}$ $\text{Apply KVL to calculate the current in the circuit. The voltage across } AB \text{ is given by:}$ $\Rightarrow V_{AB} = IR$ $\Rightarrow I(2 + 3) = 3$ $\Rightarrow I = \frac{3}{5} = 0.6$ $\text{The voltage across the voltmeter is given by:}$ $\Rightarrow V_2 = 0.6 \times 2 = 1.2 \text{ V}$ $\text{The reading of the voltmeter is } 1.2 \text{ V}$ $\text{Hence, option (3) is the correct answer.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}