Import Question JSON

Current Question (ID: 20331)

Question:

$\text{The number of electrons flowing per second in the filament of a 110 W bulb operating at 220 V is:}$ $\text{(Given } e = 1.6 \times 10^{-19} \text{ C)}$

Options:

1. $1.25 \times 10^{19}$
2. $6.25 \times 10^{17}$
3. $6.25 \times 10^{18}$
4. $31.25 \times 10^{17}$

Solution:

$P = 110 \text{ W}$ $V = 220 \text{ V}$ $I = \frac{P}{V} = \frac{110}{220} = 0.5 \text{ A}$ $\text{Number of electrons per second} = \frac{I}{e} = \frac{0.5}{1.6 \times 10^{-19}} = 3.125 \times 10^{18}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}