Import Question JSON

Current Question (ID: 20463)

Question:

$\text{Given below two statements:}$ $\text{Statement I: For diamagnetic substances, } -1 \leq \chi < 0, \text{ where } \chi \text{ is the magnetic susceptibility.}$ $\text{Statement II: Diamagnetic substances, when placed in an external magnetic field, tend to move from the stronger to the weaker part of the field.}$

Options:

1. $\text{Both Statement I and Statement II are correct.}$
2. $\text{Both Statement I and Statement II are incorrect.}$
3. $\text{Statement I is correct, and Statement II is incorrect.}$
4. $\text{Statement I is incorrect, and Statement II is correct.}$

Solution:

$\text{Hint: For diamagnetic } \mu_r < 1 \text{ and } \Rightarrow -1 \leq \chi < 0$ $\text{Explanation:}$ $\text{Also, the diamagnetic material moves from stronger to weaker fields}$ $\text{Statement I: For diamagnetic substances, the magnetic susceptibility (} \chi \text{) lies between } -1 \text{ and } 0. \text{ This is because diamagnetic substances have a negative magnetic susceptibility, which means they tend to oppose the applied magnetic field.}$ $\text{Statement II: The diamagnetic substances, when placed in an external magnetic field, experience a force that tends to move them from stronger to weaker parts of the field. This is because diamagnetic substances oppose the applied magnetic field and try to minimize their exposure to it. Therefore, Both Statements are correct. Hence, option (1) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}