Import Question JSON

Current Question (ID: 20470)

Question:
$\text{A soft ferromagnetic material is placed in an external magnetic field.}$ $\text{The magnetic domains:}$
Options:
  • 1. $\text{increase in size but no change in orientation}$
  • 2. $\text{have no relation with an external magnetic field}$
  • 3. $\text{decrease in size and change its orientation}$
  • 4. $\text{may increase or decrease in size and change its orientation}$
Solution:
$\text{Hint: when the magnetic field is applied, domains aligned in the}$ $\text{direction of the field, grow in size and those aligned in the direction}$ $\text{opposite to the field reduce in size.}$ $\text{Explanation: Soft ferromagnetic materials are easily magnetized and}$ $\text{demagnetized by external fields. This property is due to the behavior}$ $\text{of tiny regions called magnetic domains within the material. In an}$ $\text{unmagnetized state, these domains have their individual magnetic}$ $\text{moments pointing in random directions, essentially canceling each}$ $\text{other out. When an external magnetic field is applied, the domains}$ $\text{aligned in the direction of the field experience a force and tend to}$ $\text{grow in size. Conversely, domains opposing the field shrink. More}$ $\text{importantly, the external field exerts a torque on the misaligned}$ $\text{domains, causing them to rotate and align with the applied field. This}$ $\text{reorientation strengthens the overall magnetization of the soft}$ $\text{ferromagnetic material.}$ $\text{Hence, option (4) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}