Import Question JSON

Current Question (ID: 20615)

Question:
$\text{Column-I lists types of radiation, and Column-II lists their corresponding wavelengths. Match the correct pairs.}$ $\begin{array}{|c|c|} \hline \text{Column-I} & \text{Column-II} \\ \hline (A) \ \text{Microwaves} & (I) \ 100 \ \text{m} \\ (B) \ \text{Gamma rays} & (II) \ 10^{-15} \ \text{m} \\ (C) \ \text{AM radio waves} & (III) \ 10^{-10} \ \text{m} \\ (D) \ \text{X-rays} & (IV) \ 10^{-3} \ \text{m} \\ \hline \end{array}$
Options:
  • 1. $\text{A-II, B-I, C-IV, D-III}$
  • 2. $\text{A-I, B-III, C-IV, D-II}$
  • 3. $\text{A-III, B-II, C-I, D-IV}$
  • 4. $\text{A-IV, B-II, C-I, D-III}$
Solution:
$\text{Hint: } E \propto \frac{1}{\lambda}. $ $\text{Step: Identify the correct match.}$ $\text{The wavelength of the given electromagnetic radiation is as follows;} $ $(A) \ \text{Microwave} \rightarrow 10^{-3} \ \text{m} $ $(B) \ \text{Gamma Rays} \rightarrow 10^{-15} \ \text{m} $ $(C) \ \text{AM Radio wave} \rightarrow 100 \ \text{m} $ $(D) \ \text{X-Rays} \rightarrow 10^{-10} \ \text{m} $ $\text{Therefore, the correct match is A-IV, B-II, C-I, D-III.}$ $\text{Hence, option (4) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}