Import Question JSON

Current Question (ID: 20620)

Question:

$\text{Match List-I with List-II.}$ $\begin{array}{|c|c|} \hline \text{List-I} & \text{List-II} \\ \hline (A) \ \text{UV rays} & (I) \ \text{Diagnostic tool in medicine} \\ (B) \ \text{X-rays} & (II) \ \text{Water purification} \\ (C) \ \text{Microwave} & (III) \ \text{Communication, Radar} \\ (D) \ \text{Infrared wave} & (IV) \ \text{Improving visibility on foggy days} \\ \hline \end{array}$ $\text{Choose the correct answer from the options given below:}$

Options:

1. $\text{A-III, B-II, C-I, D-IV}$
2. $\text{A-II, B-I, C-III, D-IV}$
3. $\text{A-III, B-IV, C-III, D-I}$
4. $\text{A-III, B-I, C-II, D-IV}$

Solution:

$\text{Hint: Recall the applications of em-waves.}$ $\text{Step: Analyze each option.}$ $(a) \ \text{In a UV water filter system, UV (Ultraviolet) rays kill the harmful bacteria from the water. Hence the water is completely disinfected from pathogens. Therefore UV rays are used in water purification.}$ $(b) \ \text{X-rays are used as a diagnostic tool in medicine and as a treatment for certain forms of cancer. Because X-rays damage or destroy living tissues and organisms, care must be taken to avoid unnecessary or overexposure.}$ $(c) \ \text{Microwaves (short-wavelength radio waves), with frequencies in the gigahertz (GHz) range, are produced by special vacuum tubes (called klystrons, magnetrons, and Gunn diodes). Due to their short wavelengths, they are suitable for the radar systems used in aircraft navigation.}$ $(d) \ \text{Infrared waves are produced by hot bodies and molecules. This band lies adjacent to the low-frequency or long-wavelength end of the visible spectrum. Infrared waves are sometimes referred to as heat waves.}$ $\text{Hence, option (2) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}