Import Question JSON

Current Question (ID: 20622)

Question:

$\text{Match the types of radiation listed in Column-I with their corresponding applications in Column-II.}$ $\begin{array}{|c|c|} \hline \text{Column-I} & \text{Column-II} \\ \text{(Radiation)} & \text{(Applications)} \\ \hline \text{(A) Ultraviolet rays} & \text{(I) Physiotherapy} \\ \text{(B) Infrared rays} & \text{(II) Treatment of cancer} \\ \text{(C) X-rays} & \text{(III) LASIK eye surgery} \\ \text{(D) Microwave rays} & \text{(IV) Aircraft navigation} \\ \hline \end{array}$ $\text{Codes:}$ $\begin{array}{l} \text{1. A-IV, B-I, C-III, D-II} \\ \text{2. A-III, B-I, C-II, D-IV} \\ \text{3. A-II, B-I, C-IV, D-III} \\ \text{4. A-III, B-I, C-IV, D-II} \end{array}$

Options:

1. $\text{A-IV, B-I, C-III, D-II}$
2. $\text{A-III, B-I, C-II, D-IV}$
3. $\text{A-II, B-I, C-IV, D-III}$
4. $\text{A-III, B-I, C-IV, D-II}$

Solution:

$\text{Hint: Identify the applications of EM-waves.}$ $\text{Explanation: Let's match the types of radiation with their corresponding applications:}$ $\text{Ultraviolet rays: These are commonly used in LASIK eye surgery to reshape the cornea and improve vision. So, A matches with III.}$ $\text{Infrared rays: Infrared rays are commonly used in physiotherapy to promote healing and reduce pain by increasing blood circulation. So, B matches with I.}$ $\text{X-rays: X-rays are commonly used in the treatment of cancer (radiation therapy) to target and destroy cancer cells. So, C matches with II.}$ $\text{Microwave rays: Microwaves are used in aircraft navigation (radar systems) to detect objects and assist in navigation. So, D matches with IV.}$ $\text{Therefore, the correct matching is A-III, B-I, C-II, D-IV.}$ $\text{Hence, option (2) is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}