Import Question JSON

Current Question (ID: 20660)

Question:

$\text{Identify the correct statements from the following descriptions of various properties of electromagnetic waves.}$ $\text{A. In a plane electromagnetic wave electric field and magnetic field must be perpendicular to each other and direction of propagation of wave should be along electric field or magnetic field.}$ $\text{B. The energy in electromagnetic wave is divided equally between electric and magnetic fields.}$ $\text{C. Both electric field and magnetic field are parallel to each other and perpendicular to the direction of propagation of wave.}$ $\text{D. The electric field, magnetic field and direction of propagation of wave must be perpendicular to each other.}$ $\text{E. The ratio of amplitude of magnetic field to the amplitude of electric field is equal to speed of light.}$ $\text{Choose the most appropriate answer from the options given below:}$

Options:

1. $\text{(D) only}$
2. $\text{(B) and (D) only}$
3. $\text{(B), (C) and (E) only}$
4. $\text{(A), (B) and (E) only}$

Solution:

$\text{Recall the properties of electromagnetic waves.}$ $\text{In electromagnetic waves, the electric field and magnetic field are perpendicular to each other and to the direction of propagation.}$ $\text{The energy is equally divided between the electric and magnetic fields.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}