Import Question JSON

Current Question (ID: 20781)

Question:

$\text{The volume, in mL, of 0.02 M } \text{K}_2\text{Cr}_2\text{O}_7 \text{ solution required to react with } 0.288 \text{ g of ferrous oxalate in an acidic medium is:}$ $\text{[Given: Molar mass of Fe = 56 g mol}^{-1}]}$

Options:

1. $55 \text{ mL}$
2. $45 \text{ mL}$
3. $50 \text{ mL}$
4. $60 \text{ mL}$

Solution:

$\text{Given } M_{\text{Fe}} = 56 \text{ g mol}^{-1}.$ $M_{\text{C}} = 12 \text{ g mol}^{-1}, M_{\text{O}} = 16 \text{ g mol}^{-1}.$ $M_{\text{FeC}_2\text{O}_4} = 56 + (2 \times 12) + (4 \times 16) = 56 + 24 + 64 = 144 \text{g}$ $\text{Moles} = \frac{\text{Mass}}{\text{Molar mass}} = \frac{0.288 \text{ g}}{144 \text{ g mol}^{-1}} = 0.002 \text{ mol.}$ $(0.002 \text{ mol}) \times 3 = (0.02 \text{M}) \times V \times 6$ $0.006 = 0.12 \times V$ $V = \frac{0.006}{0.12} = 0.05 \text{L}$ $V = 0.05 \text{ L} \times 1000 \text{ mL/L} = 50 \text{mL.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}