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Current Question (ID: 20783)

Question:
$\text{A solution of phenol in chloroform when treated with aqueous NaOH gives compound P as a major product. The mass percentage of carbon in P is:}$ $\text{(to the nearest integer) (Atomic mass : C =12; H=1; O=16)}$
Options:
  • 1. $65$
  • 2. $69$
  • 3. $73$
  • 4. $76$
Solution:
$\text{Hint: The Mass \% of an element} = \frac{\text{mass of that element in the compound}}{\text{molar mass of the compound}} \times 100$ $\text{Step 1:}$ $\text{A solution of phenol in chloroform when treated with aqueous NaOH gives compound P as a major product. The P is salicylaldehyde. The reaction is an example of the Reimer-Tiemann reaction. The reaction is as follows:}$ $\text{The formula of salicylaldehyde is C}_7\text{H}_6\text{O}_2 \text{ and its molecular mass is } 122 \text{ g mol}^{-1}.$ $\text{Step 2:}$ $\text{The Mass \% of an element} = \frac{7 \times 12}{122} \times 100 = 69 \%$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}