Import Question JSON

Current Question (ID: 20788)

Question:
$3 \text{ g of activated charcoal was added to } 50 \text{ mL of acetic acid solution } (0.06 \text{ N}) \text{ in a flask.}$ $\text{After an hour it was filtered and the strength of the filtrate was found to be } 0.042 \text{ N.}$ $\text{The amount of acetic acid adsorbed (per gram of charcoal) is:}$
Options:
  • 1. $18 \text{ mg}$
  • 2. $36 \text{ mg}$
  • 3. $42 \text{ mg}$
  • 4. $54 \text{ mg}$
Solution:
$\text{Hint: The valency factor of acetic acid is 1.}$ $\text{Normality = Molarity as n factor of acetic acid is 1.}$ $\text{Initial mole of acetic acid} = (0.06 \times 50) \times 10^{-3}$ $\text{Final mole of acetic acid} = (0.042 \times 50) \times 10^{-3}$ $\therefore \text{mole of acetic acid adsorbed}$ $=(0.06 - 0.042) \times 50 \times 10^{-3}$ $= 0.9 \times 10^{-3}$ $\therefore \text{mass of acetic acid adsorbed}$ $=(0.9 \times 10^{-3} \times 60) \text{ g}$ $= 0.54 \text{ g or } 54 \text{ mg}$ $\therefore \text{mass of acetic acid adsorbed per gram}$ $= \frac{54}{3} \text{ mg}$ $= 18 \text{ mg}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}