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Current Question (ID: 20792)

Question:
$\text{The mass of potassium dichromate crystals required to oxidize } 750 \, \text{cm}^3 \text{ of } 0.6 \, \text{M Mohr's salt solution is:}$ $\text{(Given molar mass: potassium dichromate = 294, Mohr's salt = 392)}$
Options:
  • 1. $0.45 \, \text{g}$
  • 2. $22.05 \, \text{g}$
  • 3. $2.2 \, \text{g}$
  • 4. $0.49 \, \text{g}$
Solution:
$\text{Hint: } 6\text{Fe}^{2+} + \text{K}_2\text{Cr}_2\text{O}_7 + 14\text{H}^+ \rightarrow 6\text{Fe}^{3+} + 2\text{Cr}^{3+} + 7\text{H}_2\text{O}$ $\text{gm eqv. of Mohr's salt} = \text{gm Eqv. of } \text{K}_2\text{Cr}_2\text{O}_7$ $\frac{\text{NV(ml)}}{1000} = \frac{\text{gm}}{\text{E.w}}$ $\frac{(0.6 \times 1 \times 750)}{1000} = \frac{x}{\frac{294}{6}}$ $x = \frac{0.6 \times 750}{1000} \times \frac{294}{6} = \frac{75 \times 294}{1000}$ $= 22.05 \, \text{gm}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}