Import Question JSON

Current Question (ID: 20794)

Question:

$\text{How many moles of magnesium phosphate, } \text{Mg}_3(\text{PO}_4)_2, \text{ contain } 0.25 \text{ moles of oxygen atoms?}$

Options:

1. $0.02$
2. $3.125 \times 10^{-2}$
3. $1.25 \times 10^{-2}$
4. $2.5 \times 10^{-2}$

Solution:

$\text{Hint: Use mole concept and unitary method}$ $1 \text{ molecule of } \text{Mg}_3(\text{PO}_4)_2 \text{ contains 8 oxygen atoms.}$ $8 \text{ moles of O-atom are contained by 1 mole } \text{Mg}_3(\text{PO}_4)_2.$ $\text{Hence, } 0.25 \text{ moles of O-atom}$ $= \frac{1}{8} \times 0.25$ $= 3.125 \times 10^{-2}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}