Import Question JSON

Current Question (ID: 20795)

Question:
$\text{Two solutions of a substance (non electrolyte) are mixed in the following manner.}$ $480 \text{ mL of } 1.5 \text{ M first solution } + 520 \text{ mL of } 1.2 \text{ M second solution.}$ $\text{What is the molarity of the final mixture?}$
Options:
  • 1. $2.70 \text{ M}$
  • 2. $1.344 \text{ M}$
  • 3. $1.50 \text{ M}$
  • 4. $1.20 \text{ M}$
Solution:
$\text{Hint: } M_{\text{mix}} \cdot V_{\text{mix}} = M_1 V_1 + M_2 V_2$ $\text{Step 1:}$ $\text{The molarity of a given mixture can be calculated by using the given formula.}$ $M_{\text{mix}} \cdot V_{\text{mix}} = M_1 V_1 + M_2 V_2$ $\text{The given values are as follows:}$ $M_1 = 1.5 \text{ M}$ $V_1 = 480 \text{ mL}$ $M_2 = 1.2 \text{ M}$ $V_2 = 520 \text{ mL}$ $V_{\text{mix}} = 1000 \text{ mL}$ $\text{Step 2:}$ $\text{Calculate the molarity of the mixture as follows:}$ $M_{\text{mix}} = \frac{(1.5 \times 480) + (1.2 \times 520)}{1000}$ $= 1.344 \text{ M}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}