Import Question JSON

Current Question (ID: 20803)

Question:

$\text{Elements A and B form two compounds, } \text{A}_2\text{B} \text{ and } \text{AB}_3, \text{ with equal weights for 0.15 moles of each compound.}$ $\text{What is the ratio of the molar atomic mass of element A and element B?}$

Options:

1. $2 : 1$
2. $6 : 4$
3. $1 : 2$
4. $4 : 6$

Solution:

$\text{The formula of weight or amount is the number of moles } \times \text{ molar mass}$ $\text{Equal weights condition:}$ $0.15 \times (2M_A + M_B) = 0.15 \times (M_A + 3M_B)$ $2M_A + M_B = M_A + 3M_B$ $M_A - 2M_B = 0$ $M_A = 2M_B$ $\text{Ratio of molar atomic masses:}$ $\frac{M_A}{M_B} = \frac{2M_B}{M_B} = 2$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}