Import Question JSON

Current Question (ID: 20815)

Question:

$\text{For a given hydrocarbon, 11 moles of } \text{O}_2 \text{ is used and produces 4 moles of } \text{H}_2\text{O. The formula of hydrocarbon is:}$

Options:

1. $\text{C}_{11}\text{H}_8$
2. $\text{C}_9\text{H}_8$
3. $\text{C}_{11}\text{H}_{16}$
4. $\text{C}_6\text{H}_{14}$

Solution:

$\text{C}_x\text{H}_y + \left(x + \frac{y}{4}\right) \text{O}_2 = x \text{CO}_2 + \frac{y}{2} \times (\text{H}_2\text{O})$ $\frac{y}{2} = 4$ $y = 8$ $x + \frac{8}{4} = 11$ $x = 9$ $\text{Hence, hydrocarbon will be } \text{C}_9\text{H}_8.$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}