Import Question JSON

Current Question (ID: 20816)

Question:

$\text{For the given reaction}$ $\text{C} + \text{O}_2 \rightarrow \text{CO}_2(g)$ $\text{12 gm of C is reacted with 48 gm of O}_2 \text{ to give CO}_2.$ $\text{If volume of CO}_2 \text{ gas produced at STP is } t \text{ litres.}$ $\text{The value of } 2t \text{ is:}$ $\text{(Given: Molar volume at STP = 22.4 L/mol)}$

Options:

1. $50$
2. $42$
3. $45$
4. $54$

Solution:

$\text{C} + \text{O}_2 \rightarrow \text{CO}_2$ $\text{12 gm} \quad \text{48 gm}$ $1 \text{ mol} \quad \frac{3}{2} \text{ mol}$ $\text{Volume} = t = 22.4 \text{ L}$ $2t = 44.8 \text{ L} \approx 45 \text{ L}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}