Import Question JSON

Current Question (ID: 20837)

Question:

$\text{The neutralization occurs when } 10 \text{ mL of } 0.1\text{M acid 'A' is allowed to react with } 30 \text{ mL of } 0.05 \text{ M base } \text{M(OH)}_2. \text{ The basicity of the acid 'A' is:}$ $\text{(M is a metal)}$

Options:

1. $1$
2. $2$
3. $3$
4. $4$

Solution:

$\text{Hint: Miliequivalent of acid A = Miliequivalent of base } \text{M(OH)}_2$ $(M \times V \times n - \text{ Factor })_A = (M \times V \times n - \text{ Factor })_{\text{M(OH)}_2}$ $[n - \text{ Factor of } \text{M(OH)}_2 = 2]$ $0.1 \times 10 \times n - \text{ Factor } = 0.05 \times 30 \times 2$ $(n - \text{ Factor })_A = 3$ $\text{Hence basicity of acid A is 3.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}