Import Question JSON

Current Question (ID: 20840)

Question:

$\text{Two elements A and B which form 0.15 moles of A}_2\text{B and AB}_3 \text{ type compounds. If both A}_2\text{B and AB}_3 \text{ weigh equally, then the atomic weight of A is how many times that of B?}$

Options:

1. $8 \text{ times}$
2. $5 \text{ times}$
3. $3 \text{ times}$
4. $2 \text{ times}$

Solution:

$\text{Hint: Mole of A}_2\text{B} = \text{moles of AB}_3$ $\text{Explanation:}$ $\text{Mole of A}_2\text{B} = \text{moles of AB}_3$ $\frac{W}{2A + B} = \frac{W}{A + 3B}$ $A + 3B = 2A + B$ $2B = A$ $\text{Atomic weight of A is 2 times that of B.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}