Import Question JSON

Current Question (ID: 20846)

Question:

$\text{If 4 g equimolar mixture of NaOH and Na}_2\text{CO}_3 \text{ contains } x \text{ g of NaOH and } y \text{ g of Na}_2\text{CO}_3, \text{ then find the value of } x \text{ in grams:}$

Options:

1. $2.562$
2. $9.354$
3. $1.096$
4. $3.096$

Solution:

$\text{Given (i) } x + y = 4$ $\text{(ii) } \frac{x}{40} = \frac{y}{106} \text{ [Equimolar]}$ $Y = \left[ \frac{106}{40} \right] X$ $\text{So } x + \frac{106}{40} x = 4$ $X + 2.065X = 4$ $3.65X = 4$ $X = 1.096 \text{ gram.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}