Import Question JSON

Current Question (ID: 20847)

Question:
$\text{Methylation of 10 g of benzene gave 9.2 g of toluene.}$ $\text{Calculate the percentage yield of toluene (Nearest integer).}$
Options:
  • 1. $52\%$
  • 2. $78\%$
  • 3. $23\%$
  • 4. $43\%$
Solution:
$\text{Hint: } \% \text{ yield} = \frac{W_{\text{actual}}}{W_{\text{theoretical}}} \times 100$ $\text{Methylation: } \text{C}_6\text{H}_6 \rightarrow \text{C}_6\text{H}_5\text{CH}_3$ $\left( W_{\text{theoretical}} \right) = \frac{10}{78} \times 92$ $\% \text{ yield} = \frac{W_{\text{actual}}}{W_{\text{theoretical}}} \times 100$ $= \left[ \frac{9.2}{10 \times 92} \times 78 \right] \times 100 = 78\%$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}