Import Question JSON

Current Question (ID: 20849)

Question:

$\text{If the number of chlorine atoms in } 20 \text{ mL of chlorine gas at STP is } x \times 10^{21}. \text{ Find the value of } x:$ $\text{[Note: Assume chlorine is an ideal gas at STP]}$ $\text{[Given: } R = 0.083 \text{ L bar mol}^{-1} \text{ K}^{-1}, N_A = 6.023 \times 10^{23}]$

Options:

1. 1.0755
2. 2.3456
3. 6.0223
4. 3.1034

Solution:

$\text{Hint: Moles = } \frac{v(ml)}{22400}$ $\text{No. of moles of } \text{Cl}_2(g) = \left(\frac{20}{22400}\right)$ $\text{No. of } \text{Cl}_2(g) \text{ molecules } = \left(\frac{20}{22400}\right) N_A$ $\text{No. of Cl atoms are } = 2 \left(\frac{20}{22400}\right) \times 6.023 \times 10^{23} = 1.0755 \times 10^{21}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}