Import Question JSON

Current Question (ID: 20857)

Question:

$\text{The moles of methane required to produce 81 g of water after complete combustion is } A \times 10^{-2} \text{ mol. The value of } A \text{ is: [nearest integer]}$

Options:

1. $240$
2. $225$
3. $204$
4. $198$

Solution:

$\text{The balanced equation for the combustion of methane is:}$ $\text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O}$ $\text{Moles of } \text{H}_2\text{O} = \frac{81}{18} = 4.5 \text{ mol}$ $\text{From the equation, 2 moles of } \text{H}_2\text{O} \text{ are produced per mole of } \text{CH}_4.$ $\text{Moles of } \text{CH}_4 = \frac{4.5}{2} = 2.25 \text{ mol}$ $A \times 10^{-2} = 2.25 \Rightarrow A = 225$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}