Import Question JSON

Current Question (ID: 20865)

Question:

$\text{If the concentration of glucose (}\text{C}_6\text{H}_{12}\text{O}_6\text{) in blood is } 0.72 \text{ g L}^{-1}$ $\text{the molarity of glucose in blood is } \underline{\hspace{1cm}} \times 10^{-3} \text{ M. (Nearest integer)}$ $\text{(Given : Atomic mass of } \text{C} = 12, \text{H} = 1, \text{O} = 16\text{u)}$

Options:

1. 4
2. 6
3. 2
4. 8

Solution:

$\text{Hint: } M = \frac{W_{\text{solute}}}{M_{\text{solute}} \times V_{\text{soln (lit)}}}$ $M = \frac{W_{\text{solute}}}{M_{\text{solute}} \times V_{\text{soln (inlit)}}} = \frac{0.72}{180}$ $= 0.004 = 4 \times 10^{-3}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}