Import Question JSON

Current Question (ID: 20893)

Question:

$\text{With a ground state energy of } -13.6 \text{ eV for a hydrogen atom, what would be the energy in the second excited state?}$

Options:

1. $-6.8 \text{ eV}$
2. $-3.4 \text{ eV}$
3. $-1.51 \text{ eV}$
4. $-4.53 \text{ eV}$

Solution:

$\text{Hint: Use the formula that is, } E_n = -\frac{13.6}{n^2} \text{ eV.}$ $\text{The formula of energy of hydrogen atom is given below}$ $E_n = -\frac{13.6}{n^2} \text{ eV}$ $\text{For second excited state means, } n = 3.$ $\text{Calculate the energy in the second excited state as follows:}$ $E_3 = -\frac{13.6}{9} = -1.51 \text{ eV}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}